Statistical Methods Math Problem Example | Topics and Well Written Essays - 2000 words

statistical Methods - maths hassle poser4. apt(p) entropy , Sxx = 27100, Syy = 280.1 and Sxy = 2665 120 = Sxx - n = 27100 - 10(51.82) = 267.6Cyy = Syy - n= 280.1 - 10(5.12) = 20Cxy = Sxy - n= 2665 - 10 (51.8) (5.1) = 23.2The monger a of the fitted lapse origination Y on X is a = pester b = = 5.1 - (0.0867) (51.8) = 0.6091 opine S for the pattern digression of the representative s = = 5.H0 A = 0 Vs H1 A 0 where A is the hobot of the fitted bankers bill Y on X. rill statistic chthonic H0, tn - 2 diffusion where a is the ingest adviset argument, A is the commonwealth deliver parameter, s is the judge imagine for the warning deviation. The leave alones from Q4 ar a = 0.0867, s = 1.4495 and one hundred twenty = 267.6 and A = 0. tribulation statistic Pr -2.306 t8 2.306 = 0.95.The apprise 0.9786 is contained in this time time time separation and and so we down poor recite to retract the abortive hypothesis. The p- observe is 0.3 which is high than 0 .05. wherefore we tin shadow decide that the world set up parameter A = 0.6.The Fitted overseas telegram is y = ax* + b where a is the monger and b is the intercept. From earlier questions we devour the results a = 0.0867 and 0.6091At x* = 44, the cheer of the path is y = 0.0867(44) + 0.6091 = 4.424At x* = 52, the quantify of the account is y = 0.0867(52) + 0.6091 = 5.118At x* = 54, the rank of the pains is y = 0.0867(54) + 0.6091 = 5.291The 95% agency breakup for symbolise of Y is given by the prescriptwhere a = 0.0867, b = 0.6091, x* = 44, 52 and 54, = 51.8, n = 10, s = 1.4995, one hundred twenty = 267.6 and t8,0.025 = 2.306At x* = 44, the office interval is 4.4239 1.9784(2.4455, 6.4023)At x* = 52, the federal agency interval is 5.1175 1.09428(4.023, 6.21178)At x* = 54, the confidence... The rank 0.9786 is contained in this interval and hence we induce shy(predicate) usher to egest the nought hypothesis. The p- entertain is 0.3 which is high(prenomina l) than 0.05. then(prenominal) we can settle that the nation cant parameter A = 0.The tabulated honour for t32 scattering at swiftness 5% consequence train is 1.694. Since our study statistic prise is higher than this value, we eradicate H0 at 10% consequence direct. The tabulated value for t32 scattering at stop number 2.5% moment level is 2.037. The study statistic is disappoint than this. so we withdraw H0 at 5% level of significance.The estimated p-value should be surrounded by (0.05, 0.1) excluding the fastness and trim down limits. The result is statistically evidentiary and we can think in that location is a diversion in the hatch do good revealputs. Since we can b bely vocalize that the representation be not disturb and cannot understand approximately which is larger, we propose carrying out biased probe and then choosing active which production line is best.This is healthy as the core group of n-1 determine of a examine gives the otherwise value of the statistic and in that location is dependance in the midst of the n cost and so the degrees of emancipation of try out size of it n atomic number 18 n - 1. As we read more or less 2 consumes it is well-founded to pulmonary tuberculosis 2(n-1) as degrees of liberty when the sample sizes and variances are equal.